🔬 Beam Vibration Laboratory

Master Structural Dynamics Through Interactive Learning

Explore natural frequencies, mode shapes, and energy exchange with real-time physics simulations

🎬 Live Simulation

Animation Speed
Deformed Shape (Time Domain)
Energy Distribution
Time Response (Oscillation)

Vibration Mode

Mode 1 (Fundamental) - Single hump pattern. Lowest frequency, most common in real structures.

Key Metrics

Natural Frequency
0.00
Hz (cycles/sec)
Period
0.00
seconds
Max Deflection
0.00
millimeters
Peak Stress
0.00
megapascals
🎯 Observation: Watch how frequency changes as you adjust parameters. Stiffer, shorter beams vibrate faster. Heavier beams vibrate slower. This is the fundamental principle of structural dynamics!

⚙️ Interactive Parameters

Geometry Configuration
Length (m) 2.0
↓ Length = ↑ Frequency (inverse square relationship)
Height (mm) 100
↑ Height = ↑ Frequency (cubic relationship - most powerful)
Width (mm) 50
Linear effect on bending stiffness
Material Properties
Young's Modulus (GPa) 200
↑ Stiffness = ↑ Frequency (square root relationship)
Density (kg/m³) 7850
↑ Mass = ↓ Frequency (inverse square root)
Quick Actions
🎯 Challenge Quest:
Can you find three different beam configurations that all have a natural frequency of ~5 Hz? What property combinations achieve this?

🎮 Progress Tracker

Level 1: Novice
Experience Points 0/100

📚 Learning Path

👁️
Observe
Watch beam vibrate
📐
Length Effect
Adjust length
📏
Height Effect
Cubic relationship
🔬
Materials
Compare 4 types

🏆 Achievements

👁️ First Look
Next Step
Try changing the length slider to discover how it affects frequency!

🔍 Guided Investigation Path

1 Observe the Fundamental Motion
Watch Mode 1 carefully. The entire beam moves as a single arc—up and down, up and down. This sinusoidal motion repeats at the natural frequency. Count the oscillations: how many times per second does it complete a full cycle? That's the frequency in Hz.
2 Pause and Analyze Shapes
Click pause. Now you see the maximum deformed shape. The beam bends smoothly from one support to the other, forming a gentle arc. This is one extreme of the motion. The other extreme is an equal arc in the opposite direction. The beam oscillates between these two shapes.
3 Experiment: The Length Effect
Slowly increase the beam length from 2.0 m to 5.0 m. Prediction: What will happen to the frequency? Write your prediction before adjusting. Then change it and observe. The frequency should decrease dramatically (inverse square law). Why? Longer beams are more flexible—they bend easier.
4 Experiment: The Height Effect
Reset to defaults. Now slowly increase height from 100 mm to 200 mm (doubling it). Prediction: What happens? The frequency increases by 8× (2³). This cubic relationship makes height the MOST powerful design parameter. Tall, slender beams (like skyscrapers) are very stiff.
5 Experiment: Material Matters
Click "Steel" (E=200 GPa). Then click "Aluminum" (E=70 GPa). Notice aluminum has much lower Young's modulus, so the frequency is lower. But not 1/3 lower—only 1/√2.86 lower (square root law). Material stiffness has a moderate effect.
6 Discover Mode Shapes
Click "Mode 2". Now you see two humps! The middle of the beam moves opposite to the ends. This requires more energy to excite (higher frequency). Click "Mode 3" for three humps. Each additional mode is progressively harder to activate in real structures.
7 Test the Formula
The formula f = (λ²/2πL²)√(EI/ρA) predicts everything you've observed. Increasing E or I increases f. Increasing L or ρA decreases f. The specific powers (inverse square for length, cube for height, square root for properties) come from solving the physics equations.
8 Real-World Connection
Engineers use this principle to design safe buildings. For earthquakes, you want natural frequencies away from typical ground vibrations (0.5-10 Hz). For wind, you want frequencies above 0.1 Hz. For machinery, avoid the running speed frequency!
🏆 Final Quest:
Design an aluminum beam (not steel) that vibrates at exactly 3.0 Hz with a length of 3.0 meters. What height and width do you need? This is what real engineers solve daily!

📊 Mode Comparison & Behavior

All Three Modes Displayed Simultaneously (Current Beam Configuration)
Mode 1
0.00
Hz
Mode 2
0.00
Hz
Mode 3
0.00
Hz

🔍 Parameter Sensitivity Analysis

Length Effect
f ∝ 1/L²
Doubling length = ¼ frequency
4× Reduction
Height Effect
f ∝ h³
Doubling height = 8× frequency
8× Increase
Width Effect
f ∝ √w
Doubling width = 1.41× frequency
1.41× Increase
Stiffness Effect
f ∝ √E
Doubling E = 1.41× frequency
1.41× Increase
Density Effect
f ∝ 1/√ρ
Doubling density = 0.71× frequency
29% Reduction
Design Strategy
To increase frequency: maximize height, minimize length, use stiff materials, and reduce mass.

📈 Material Comparison Table

Material E (GPa) Density (kg/m³) Mode 1 Freq Relative Stiffness
Steel 200 7,850 - 100%
Aluminum 70 2,700 - 56%
Wood 12 600 - 18%

🎓 Complete Mathematical Theory

The Governing Equation

∂⁴y/∂x⁴ + (ρA/EI)(∂²y/∂t²) = 0

This fourth-order partial differential equation describes transverse displacement y(x,t) of a beam subject to no external forces (free vibration).
Physical Interpretation: The left term represents how the bending moment changes (related to curvature). The right term represents how mass accelerates. These must balance for free vibration.

Boundary Conditions (Simply Supported)

At x = 0 and x = L:
y(0,t) = 0 and y(L,t) = 0 (no vertical displacement)
∂²y/∂x²(0,t) = 0 and ∂²y/∂x²(L,t) = 0 (no moment)

These constraints force the solution to be a sine function!

Separation of Variables Solution

Assume y(x,t) = Y(x)·T(t)

This splits the PDE into two ODEs:
Y''''(x) - β⁴Y(x) = 0
T''(t) + ω²T(t) = 0

where β⁴ = ρAω²/(EI)
Spatial Solution: The boundary conditions force Y(x) = sin(nπx/L) for n = 1, 2, 3, ...

Temporal Solution: T(t) = A·cos(ωt) + B·sin(ωt) — sinusoidal oscillation

Natural Frequencies (Eigenvalues)

From the constraint λ = nπ (where λ is the eigenvalue):

ω_n = (λ_n²/L²)√(EI/ρA)

f_n = ω_n/(2π) = (λ_n²/2πL²)√(EI/ρA)

λ_1 = π ≈ 3.14 → First mode constant ≈ 9.87
λ_2 = 2π ≈ 6.28 → Second mode constant ≈ 39.48
λ_3 = 3π ≈ 9.42 → Third mode constant ≈ 88.83
Why These Specific Constants? They come from solving sin(λ) = 0 with the boundary conditions. The first non-trivial solution is λ ≈ π (not exactly, but 9.87 comes from numerical solution).

Modal Superposition Principle

Complete solution: y(x,t) = Σ[A_n·sin(nπx/L)·cos(ω_n·t + φ_n)]

The motion is a superposition of all possible modes. Higher modes require more energy to excite, so they usually have smaller amplitudes (A_n decreases with n).
Energy Perspective: Each mode stores energy independently. Total energy = kinetic + potential. As the beam oscillates, energy constantly exchanges between these two forms. Natural frequency represents maximum efficiency of this energy exchange.

Moment of Inertia Derivation

For rectangular cross-section (width b, height h):

I = ∫∫ y² dA = ∫₀^h ∫₀^b y² dx dy

I = (1/12)·b·h³

The h³ term explains why height is so powerful!

Design Implications

Resonance Avoidance: If external forcing frequency matches natural frequency, response amplitude grows without bound. Engineers design structures to have natural frequencies far from excitation sources.
Practical Damping: Real beams have damping (energy dissipation through material deformation, air resistance, etc.). This prevents infinite amplification and causes oscillations to decay over time.
Multi-Degree-of-Freedom Systems: Real structures have infinite DOF. We extract the first few modes (usually 3-10) and ignore higher ones because they carry little energy and are rarely excited.
The Complete Picture: Beam vibration is one of the foundational problems in structural mechanics. It appears everywhere: buildings, bridges, aircraft wings, machine tools, turbines. Understanding this one system unlocks understanding of all linear vibration problems.